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goody613: the rule that every rule has an exception?
yeah
“I always lie” is another one… it cant possibly be true because he must be lying when he says it!
A boy drops a rubber ball from a height of 8 feet above a concrete floor. Each time the ball hits the ground it bounces up 75% of its previous maximum height (it reaches 6 feet on its first bounce, 4.5 feet on the second bounce…). What is the total vertical distance the ball will eventually travel?
Dr. Pepper?? wow, pass a can
and a can for me too, please.
do you know that i wrote that message when i saw your name and i forgot to read your riddle?? had to go back a second time
dr. pepper: well technically if it always went 75% of the distance it was at then it would never stop bouncing (just like if ur 10 feet from a wall and keep walking half the distance u will never reach it) nbot sure if this is the answer…if its not it would depnd on how high the ball is (so that ui could figure out at which point it would stop bouncing
moish01:haha
yeah but gravity, so it’s gotta stop at some point. i don’t know this stuff but i do know common sense.
moish01: i know but that is why the question makes no sense…but like i said it could b but u would need to know the height of the ball so that u can no at which point the ball will stop bouncing…once the height of the ball and the amoint it will bounce is the same then it is resting on the ground…im making this all up but i think it makes sense
ah. i hear.
moish01: haha really? well mayb u could explain it to me bec im a little confused 😛 jkjk
Dr. Pepper-
Welcome back!
I hope the mishpacha is doing well.
The riddle thread missed you.
On to the task at hand…
The denominator of the fractional equivelent of the missing percentage is how many times the original number will be just short of.
In other words, if it bounces 50%, and 1/2 is the missing portion of 100% the total would be just shy of 2 * the original height.
Since it bounced 75%, and 1/4 is the missing portion of 100% the total would be just shy of 4 * the original height.
The answer is: just shy of 24 feet.
I Can Only Try, did you factor in the bounce on the way up and down, or only the way down? 8 feet down, 6 feet up, 6 feet down, 4.5 feet up, 4.5 feet down. That is 29 feet already, and it is still bouncing. That was the “chap” of the riddle
… unless the up and down are both counted, in which case I guess it’s the six original feet, plus 2 * (just shy of 18 feet) which would equal just shy of 42′ altogether. (I’d better add the caveat “I think”). 🙂
JayMatt19-
I think you’re right.
Please see my prior post, which I just submitted before seeing your answer.
…and my remedial reading teacher pointed out that the original drop said 8′, not 6′
I’m going down to the minors, to work on my swing. ;p
I can only try- It’s great to be back here. The family is great thanks for asking. This morning I saw the baby kicking her feet while deep in concentration- it was the cutest thing- I thought she was trying to figure out where her center of gravity was so she could try to roll over. My wife figured out exactly what she was doing and made me change the diaper…
It’s really touching to see that I was missed. I’m afraid to log on at home when I should be helping my wife and at work our department was assigned some challenging projects so I’m a little reluctant to log on over there (I’m still trying to explain to facilities why I had 3,121 coconuts, 4 colleagues and a monkey in my 5′ X 7′ cubicle…).
Hopefully we should be finished the projects by early July and I’ll be able to return to this thread full time.
moish01- The soda with the same name as me is Dr Pepper (not Dr. since it’s not a real doctor), I hope this removes any confusion.
teen- The problem says “What is the total vertical distance the ball will eventually travel?” not “What is the total vertical distance traveled by the ball when it comes to a complete stop?”. The ball will never come to a complete stop but the vertical distance travelled will eventually reach a limit as the amount of time elapsed approaches infinity, what is this limit?
The answer is 56 feet.
I can only try- 24 feet is the upward distance, multiply that by two for the distance it travelled down each time it bounced up plus the original 8 foot drop gives the correct answer of 56 feet.
sure doc. i’ll keep that little . in mind.
Dr. Pepper – you seem like a wise man but the correct answer is -8 feet. The total distance traveled can be easily calculated since it is a telescoping sum:
Distance = – 8 + 6.5 – 6.5 + 4.875 – 4.875 + …..
‘. = – 8(+ 6.5 – 6.5)+(4.875 – 4.875)+(…..
= – 8
gleeg- if you studied physics at all, you would realize that negative/positive signs are there only to signify direction (left or right from the starting place). He asked for the “total vertical distance” which would be the absolute value of the distances… or scalar vs vector quantities…
am I right Dr. Pepper?
does anyone have a riddle that doesnt require such…uhhh…mathematical knowledge?
Yeah,
what is greater than G-d
more meaner than the devil
a poor man has it
a rich man needs it and when you eat it you die?
22oldgold: nothing
nothing is greater than god
nothing is meaner than the devil
a poor man has nothing
a rich man needs nothing (else)
and when you eat nothing you die
😀 make sense?
more meaner? english, dude!
gleeg-
The distance traveled can not be a negative number. If the question was how much higher is the ball when it stops bouncing then -8 would be correct.
Special for valentines day;
You have a regular deck of 52 cards with two cards missing (you don’t know which 2).
A card is selected at random, what is the probability that the suit of the card picked is Hearts?
If I asked the other guy which road not to take, which one would he tell me?
They would both lead you to the ideal path
What 4 Brachos are said once a year, every year?
(Please note, this is geared towards Jews in the diaspora, therefore, brachos like “al achilas Marror would be incorrect)
dr pepper:
is it a 24% chance?
Dr. Pepper-
I’ll go with “Teen”s answer. Unlike the “Monte Hall” puzzle, if the missing cards are truly random I don’t think the odds are affected (four suites plus two wildcards, I think – I don’t really know cards).
JayMatt19-
1) Tal 2) Geshem 3) Biur Chometz 4) I’ll (probably) kick myself for missing this one.
There is no Bracha for Tal, nor for geshem. They are t’fillas. I am referring to brachos!
Biur chametz is correct thoug (3 left!)
jaymatt what is the diaspora? and whats it got to do with marror?
jaymatt: how about the one where u find the chametz (forgot the name of it)
1) Neiros Erev Yom Kippur
2) Biur Chometz
3) Bircas Ilanos
4) The chasimah for Nachem (on tisha b’av by mincha – though some sefardim say it 3x)
Note: For those of litvish origins, the brocho of “Haposeach lonu shaarei rachamim” is also said once a year (instead of “Yotzer ohr u’voray choshech” on Yom Kippur). But some other nusachos never say it, and some others say it on Rosh Hashono as well. So litvaks could count it as a fifth.
Here is a riddle of my own:
In what situation might one not be allowed to daven shemona esrai – even though one is in a perfectly kosher shul – because of a bowing-down problem?
JayMatt19-
Lehadlik nair shel Yom haKipurim (not sure if you’re counting this since men usually don’t make this brocha)
Eruz Chatzeiros? dont people do that once a year?
hmm… what about one that not everyone says, but that one normally only says once a year… ie: the bracha a father says at his son’s bris? it is possible though to have two sons born within a year who were not twins but that is not the norm… ok, not everyone has a son every year but I do know some families where it goes almost without fail Bli Ayin Hara…
the bracha for megila? wait, you do that though in the morning and the evening…
ok, I am not sure if any of these are what you are looking for, but it was a try…
JayMatt19-
I gave up and googled it.
I never would’ve gotten 3 or 4, although I should’ve gotten 3.
Good question(s).
Yes ames you are correct, the answer is 1/4.
Here’s how I solved the problem when I had it on an exam.
There are 1,326 unique ways to choose 2 cards from a standard 52 card deck. (52 x 51 / 2 = 1,326. We divide by two since order doesn’t matter i.e. a seven of spades and a king of clubs is the same group as a king of clubs and seven of spades.)
Of the 1,326 possibilities 78 include 2 hearts (13 * 12 / 2= 78), 507 include one heart and one non-heart ( 2 * (13 * 39 / 2) = 507) and 741 consist of two non-hearts (39 * 38 / 2 = 741). (Please note that 78 + 507 + 741 = 1,326.)
If two hearts are missing from the deck the probability of picking a heart is 11/50.
If one heart is missing from the deck the probability of picking a heart is 12/50.
If no hearts are missing from the deck the probability of picking a heart is 13/50.
So the probability of two hearts missing (78/1,326) x the probability of picking a heart (11/50) = (78/1,326)*(11/50).
Summing up the probabilities from all three scenarios gives us (78/1,326)*(11/50) + (507/1,326)*(12/50) + (741/1,326)*(13/50) = 1/4.
when can you not bow down?? if there is an untzniyus lady (for some reason) on the men’s side… You said in a perfectly kosher shul, so I thought that refered to no A”Z there, but maybe there was a person there that should not be there. (Or what about on a stone floor on yom kippur when the chazzen bows down??)
ames: i dont think u had all that in mind haha
dr pepper: uhhh sure haha if u say so lol
what i did was find the chance of 2 hearts beings picked out first then the chance that if those 2 hearts were picked of picking another heart but i see where i went wrong i automatically assumed 2 hearts were picked right away but i realize now its not for sure like that that
dr. pepper: i wonder if anyone besides you(and probably Icot) understood that.$
squeak-
I doubt this is the answer you’re looking for, but are you referring to one who may have difficulty controlling their bodily emissions?
Dr. Pepper-
Your explanation was detailed, technical, correct and way over my head.
I would simply say that if any number of cards are removed from a deck at random, the odds that the next card in the deck is a heart are 1/4 (a 52 card deck with no wild-cards are included).
well squeek- watz the answer? :o)
I can only try
That’s correct, no matter how many cards are removed (up to 51 and assumning that it is not known which cards are removed) the probability of the picking a heart will be 1/4. Let’s see you prove it for where 32 cards are removed.
(Hint- there are 125,994,627,894,135 different ways that 32 cards can be chosen from a deck of 52 where order doesn’t make a difference. Hope this helps!)
Dr. Pepper, I saw your post in the Funny Shidduchim Stories thread, about your ’89 camp days. I gotta say you’re a lot younger than I imagined. Embarassingly enough, when you hinted at your mazal tov a few months back (without saying exactly for what), I was about to say that you should have a lot of nachas with this einekel and all you einekelach! Thankfully, by time I got back to post you already indicated it was your child.
The Big One-
My wife can’t stop laughing at your post. What did I say that made you think I am older than I really am?
Dr. Pepper, I’m glad to have brought laughter to your family 🙂
I can’t pinpoint anything in particular, but probably your vast sum of mathematical genius played a role, as well as the sophistication of your other postings.
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