- This topic has 18 replies, 11 voices, and was last updated 11 years, 10 months ago by .
-
Posts
-
That’s actually really funny – he now has 2,543 posts, a number in which all the digits are different and when rearranged are consecutive. The year 2,013 is the first year since 1,987 to have all unique digits, and when rearranged they are also consecutive. The chances of two numbers having that characteristic is 0.07%, even if you include numbers like 1,809 which string from “below” zero to above zero. If you only count above zero, e.g. 3,201, it’s a 0.035% chance. (yes, the odds of SOME numerically significant similarity between the two numbers occurring is a lot higher, but it’s still neat :P)
Cool, thanks. I must have signed up during chanuka vacation in yeshiva that year.
How can both 2013 and 1987 be consecutive? If you count the zeros, then 2013 is but 1987 is not. And if you dont count zeros, then every year from 2000-2010 (except 2002) was also all unique digits.
Wow uneeq what made you check popas profile?
are you that into the CR and it’s trolls?
midwesterner – 1987 is NOT consecutive, it’s just all unique digits like 2013, which none of the years in between share with them. 2013 and 2543 are both consecutive and unique.
midwesterner- i think he meant to use the zeros in the # loop or not, so 7 8 9 0 1 2 3 vs 7 8 9 1 2 3. Not to skip the zeros though. so if u count the zero as in the cycle 2013=0123 or 1809=8901, and if you skip zeros, 1987= 7891.
Happy cranniversary !!!!
Just to clarify….I never meant to SKIP zero. The two options I was thinking of were either to have zero only count as the low end of the string, because zero is actually the smallest value digit, so the only options would be numbers that contain 0-1-2-3, 1-2-3-4, 2-3-4-5, 3-4-5-6, 4-5-6-7, 5-6-7-8, and 6-7-8-9, OR to allow zero to connect the lowest digits to highest digits (kind of like an ace connects the lows and the highs in the card game spit), which would also allow 7-8-9-0, 8-9-0-1, and 9-0-1-2. There are 24 possible orders for any four unique digits, so that would be 168 possibilities if zero only counts low, 240 possibilities if zero can “string”. There are 9,000 positive integers that contain 4 digits, so that’s 168/9000 or 1.8667% if zero is low, 240/9000 or 2.6667% if zero strings. To have two such numbers independently, you just square the odds, so 0.0348% if zero is low, 0.0711% if zero strings.
My sentence “The year 2,013 is the first year since 1,987 to have all unique digits, and when rearranged they are also consecutive” was admittedly confusing lol. ‘They are also consecutive’ was not referring to the 1,987; following either of the two possibilities, 1987 would not be consecutive (and I think just deciding to “ignore” zero wouldn’t be a very fair move, saysme, but thanks for the thought). The only commonality between 1987 and 2013 is the uniqueness of digits, which none of the years between them have.
Indeed, it was my wooden cranniversary.
I was looking at his profile to see if women are still Jewish.
And…?
frummy- ah gotcha! So next consecutive would be 2031, and 2013-2019 all are unique. Thanks for the clarification
SaysMe – precisely 🙂
Uneeq,
The latter.
You saw that in his profile?
How can I see PBA’s profile? You’ve all gotten me really curious.
click on his username. That works for any user who hasn’t changed their name.
popa’s link takes you to his “Lying on YWN” thread. You need to enter http://www.theyeshivaworld.com/coffeeroom/profile/popa_bar_abba (which is, by the way, the same link for all user names (that haven’t been fiddled with), just with their extension at the end).
Only in the CR can a happy birthday thread turn into a math discussion.
- You must be logged in to reply to this topic.