Reply To: Elementary Mathematical Equation

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The smallest positive integer solution of the equation x^n + y^n + z^n for n>2, is 1.
We can assign x=y=0 which gives us x^n+y^n=0^n+0^n=0.
Then, we want to assign z^n=1 (since 1 is the smallest positive integer, and the ideal solution to the problem), which can be achieved by setting z=1, or 1^n=1 for n>2
Thus, 0+0+1=1